document.write( "Question 46732: The traveling squad for a basketball team consists of two centers, five forwards, and four guards. In how many ways can the coach select a starting team of one center, two forwards, and two guards? \n" ); document.write( "

Algebra.Com's Answer #327591 by JWG(21) $\"\"$ $\"About$

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Hopefully someone that knows better can confirm or correct, but I think the answer is 120. Here is how I got there:
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\n" ); document.write( "Center: 2 ways to select one center
\n" ); document.write( "Forward: 5C2 or 10 ways to select two forwards
\n" ); document.write( "Guard: 4C2 or 6 ways to select two guards
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\n" ); document.write( "For the forwards and guards, I used what is called a Combinations Formula. One can look up how to use it on Wikipedia or use the =COMBIN(x,y) function in Excel. The long hand version that one would have to use to solve by hand is 5!/2!*(5-2)! As you can see, for forwards I had '5' for the number of available forwards I had to choose from and '2' for the amount that I would select from the available group. Now onto the rest of the solution...
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\n" ); document.write( "I multiply the possibilities that I have for each position: 2*10*6 which equals 120. \n" ); document.write( "

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