document.write( "Question 477945: Please show me how to solve the following inequalities for X:\r
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document.write( "1. 6 > x + 4 >4\r
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document.write( "2. 2x > x > 10 > -x\r
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document.write( "Also the next category says Solve each of the following for x in terms of other variables. (Assume none of the variables equals zero)...\r
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document.write( "3. abx = c\r
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document.write( "4. a + bx = c + dx\r
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document.write( "5. ax - x = bx + c\r
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document.write( "Many thanks for your help. I was getting a migrane trying to solve this!!!! \n" );
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Algebra.Com's Answer #327553 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the best way to solve these is to break them up into segments and then combine the answers at the end. \n" ); document.write( "question number 1: \n" ); document.write( "6 > x + 4 > 4 \n" ); document.write( "break this up into: \n" ); document.write( "6 > x + 4 \n" ); document.write( "x + 4 > 4 \n" ); document.write( "solve each separately: \n" ); document.write( "subtract 4 from both sides of 6 > x + 4 to get 2 > x \n" ); document.write( "subtract 4 from both sides of 2 + 4 > 4 to get x > 0 \n" ); document.write( "if 2 > x then x < 2 \n" ); document.write( "if x > 0 then 0 < x \n" ); document.write( "combine this answer into: \n" ); document.write( "0 < x < 2 \n" ); document.write( "plug a value of x that is greater than 0 and less than 2 into the original equation and you'll see that it is satisfied. \n" ); document.write( "plug a value of x that is not greater than 0 or is not less than 2 into the original equation and you'l see that it is not satisfied. \n" ); document.write( "question number 2: \n" ); document.write( "2x > x > 10 > -x \n" ); document.write( "break this up into: \n" ); document.write( "2x > x \n" ); document.write( "x > 10 \n" ); document.write( "10 > -x \n" ); document.write( "solve each separately. \n" ); document.write( "subtract x from both sides of 2x > x to get x > 0 \n" ); document.write( "leave x > 10 as is \n" ); document.write( "multiply both sides of 10 > -x by -1 to get -10 < x \n" ); document.write( "this is the same as x > -10 \n" ); document.write( "multiplying both sides of an inequality by a negative number reverses the inequality. \n" ); document.write( "combine this answer into: \n" ); document.write( "x > 10 because if x > 10 then it satisfies x > 0 and it satisfies x > -10. \n" ); document.write( "if you substitute into the original equation of 2x > x > 10 > -x, you'll see that if x > 10 then the equation is satisfied and if x <= 10 the equation is not satisfied. \n" ); document.write( "question number 3: \n" ); document.write( "abx = c \n" ); document.write( "divide both sides of this equation by ab to get: \n" ); document.write( "x = c/ab \n" ); document.write( "question number 4: \n" ); document.write( "a + bx = c + dx \n" ); document.write( "subtract dx from both sides of this equation to get: \n" ); document.write( "a + bx - dx = c \n" ); document.write( "subtract a from both sides of this equation to get: \n" ); document.write( "bx - dx = c - a \n" ); document.write( "factor out the x to gtet: \n" ); document.write( "(b-d)x = c-a \n" ); document.write( "divide both sides of this equation by (b-d) to get: \n" ); document.write( "x = (c-a)/(b-d) \n" ); document.write( "question number 5: \n" ); document.write( "ax - x = bx + c \n" ); document.write( "subtract bx from both sides of this equation to get: \n" ); document.write( "ax - bx - x = c \n" ); document.write( "factor out the x to get: \n" ); document.write( "x(a - b - 1) = c \n" ); document.write( "divide both sides of this equation by (a-b-1) to get: \n" ); document.write( "x = c/(a-b-1)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |