document.write( "Question 478008: suppose 13 percent of all credit card holders eventually become deliquent. Suppose we select a random sample of 10 credit card holders. find the probability that : exactly 2 become deliquent, 3 or 4 become delinquent, 1 becomes delinquent, the mean of the probability distribution is, the standard deviation of the probability distribution is \n" ); document.write( "
Algebra.Com's Answer #327533 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
suppose 13 percent of all credit card holders eventually become deliquent. Suppose we select a random sample of 10 credit card holders.
\n" ); document.write( "------
\n" ); document.write( "Binomial Problem with n = 10 and p = 0.13
\n" ); document.write( "---------------------------\r
\n" ); document.write( "\n" ); document.write( "Find the probability that : exactly 2 become deliquent,
\n" ); document.write( "P(x=2) = 10C2(0.13)^2(0.87)^8 = 0.2496
\n" ); document.write( "---------------------------------------- \r
\n" ); document.write( "\n" ); document.write( "3 or 4 become delinquent,
\n" ); document.write( "10C3(0.13)^3(0.87)^7 + 10C4(0.13)^4(0.87)^6
\n" ); document.write( "---------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "1 becomes delinquent
\n" ); document.write( "10C1(0.13)(0.87)^9
\n" ); document.write( "------------------------------\r
\n" ); document.write( "\n" ); document.write( "The mean of the probability distribution is np = 10*0.13 = 1.3
\n" ); document.write( "------------------------------\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The standard deviation of the probability distribution is sqrt(npq)
\n" ); document.write( "= sqrt(1.3*0.87) = 1.0635
\n" ); document.write( "=============================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "============
\n" ); document.write( " \n" ); document.write( "
\n" );