document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=477874>Question 477874</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve for x\r<BR>\n" );
document.write( "\n" );
document.write( "15^10x=11^-x+3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #327500 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=327500\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve for x <BR>\n" );
document.write( "15^10x=11^-x+3<BR>\n" );
document.write( "**<BR>\n" );
document.write( "Whenever you have the variable in the exponents, the solution usually requires the use of logarithms.<BR>\n" );
document.write( "15^10x=11^(-x+3)<BR>\n" );
document.write( "10xlog 15=(-x+3)log 11\r<BR>\n" );
document.write( "\n" );
document.write( "10x/(-x+3)=log11/log15=.8855<BR>\n" );
document.write( "10x=(-x+3)(.8855)=-.8855x+2.6564<BR>\n" );
document.write( "10.8855x=2.6564<BR>\n" );
document.write( "x=2.6564/10.8855=.244<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Check<BR>\n" );
document.write( "15^10x=15^2.44=740.7347=741 (rounded)<BR>\n" );
document.write( "11^x-3=11^2.756=741.4438=741 (rounded) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );