document.write( "Question 477899: I need help setting up the equations. I almost have it I think, but I want to make sure.\r
\n" ); document.write( "\n" ); document.write( "Solution A is 20% acid. Find the amount of Solution A and the amount of pure water needed to make 5 liters of a new solution that is 18% acid.\r
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Algebra.Com's Answer #327475 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "Solution A is 20% acid ...to new solution 5L that is 18% acid 
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document.write( "Will set question up as to the % of water
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document.write( "Let x represent the amount of pure water 
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document.write( "and (5L-x) represent the amount of 80% water solution (20% acid)
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document.write( "Mixing to form a 82% water solution
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document.write( "x + .80(5-x) = .82*5
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document.write( "    .20x =  .02*5
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document.write( "       x = .02*5/.20
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document.write( "       x = .5L of water \n" );
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