document.write( "Question 477895: Walt made an extra $9000 last year from a part-time job. He invested part of the money at a 9% annual rate of interest, and the rest at 8% annual rate of interest. At the end of the year, he made a total of $770 in interest. How much was invested at 8%?
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Algebra.Com's Answer #327462 by mangopeeler07(462) $\"\"$ $\"About$

You can put this solution on YOUR website!
9000=total money
\n" ); document.write( "Money at 9%=x
\n" ); document.write( "Money at 8%=9000-x (because it's the rest)\r
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\n" ); document.write( "\n" ); document.write( "increase interest=770. so 9000+770= 9770.\r
\n" ); document.write( "\n" ); document.write( "So set up the equation:
\n" ); document.write( " $\"1.09x%2B1.08%289000-x%29=9770\"$ Because x+ 9% of x and (9000-x) + 8% of that equals 9770.\r
\n" ); document.write( "\n" ); document.write( "Simplify
\n" ); document.write( " $\"1.09x%2B9720-1.08x=9770\"$ \r
\n" ); document.write( "\n" ); document.write( "Simplify again
\n" ); document.write( " $\".01x%2B9720=9770\"$ \r
\n" ); document.write( "\n" ); document.write( "Subtract 9720 from both sides.
\n" ); document.write( " $\".01x=50\"$ \r
\n" ); document.write( "\n" ); document.write( "Divide each side by .01\r
\n" ); document.write( "\n" ); document.write( " $\"x=5000\"$ \r
\n" ); document.write( "\n" ); document.write( "Therefore:\r
\n" ); document.write( "\n" ); document.write( "$5000 was invested at 9%, and $4000 was invested at 8%. \n" ); document.write( "

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