document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=49232>Question 49232</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me answer this problem:<BR>\n" );
document.write( "   Worksheet says:  Solve each system by substitution.  check your solution.<BR>\n" );
document.write( "a-1.2b = -3<BR>\n" );
document.write( "0.2b+ 0.6a= 12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #32743 by </B><A HREF=/tutors/aboutme.mpl?userid=Osran_Shri><B>Osran_Shri(18)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Osran_Shri><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=32743\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> here we have to find out values of \"a\" and \"b\" by substitution method and verify the solution.\r<BR>\n" );
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document.write( "a-1.2b = -3    ...............Equation-1<BR>\n" );
document.write( "0.2b+ 0.6a= 12 ...............Equation-2\r<BR>\n" );
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document.write( "From Equation-1:<BR>\n" );
document.write( "a = (-3 + 1.2b )= (1.2b - 3)...Equation-3\r<BR>\n" );
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document.write( "Now substitute \"a\" from above (Equation-3) into Equation-2 to get following equation:\r<BR>\n" );
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document.write( "0.2b + 0.6(1.2b-3)=12<BR>\n" );
document.write( "0.2b + 0.72b - 1.8 = 12<BR>\n" );
document.write( "0.92b - 1.8 = 12<BR>\n" );
document.write( "0.92b = 12 + 1.8 = 13.8<BR>\n" );
document.write( "b = 13.8/0.92 = 15\r<BR>\n" );
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document.write( "Therefore b = 15 Substitute b=15 into Equation-3 to get \"a\" as below:\r<BR>\n" );
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document.write( "a = 1.2b - 3 = 1.2*15 - 3 = 18 - 3 = 15\r<BR>\n" );
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document.write( "Hence values of : a=15 & b=15\r<BR>\n" );
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document.write( "Verification of Solution:<BR>\n" );
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document.write( "Substitute values of a & b into Equation-1 to get -3 as below:\r<BR>\n" );
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document.write( "a-1.2b = 15 - 1.2*15 = 15 - 18 = -3 --------> a-1.2b= -3\r<BR>\n" );
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document.write( "Now substitute values of a & b into Equation-2 to get 12 as below:\r<BR>\n" );
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document.write( "0.2b+ 0.6a = 0.2*15 + 0.6*15 = 3 + 9 = 12 -------> 0.2b+0.6a=12\r<BR>\n" );
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document.write( "thats it....<BR>\n" );
document.write( "B.Shridhar<BR>\n" );
document.write( " </SPAN>\n" );
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