document.write( "Question 5211: I've been working on word problems, but this one has me stumped.
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document.write( "A car travels 120 miles. A second car; traveling 10 mph faster than the first car, makes the same trip in one hour less time. Find the speed of each car. \n" );
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Algebra.Com's Answer #3274 by glabow(165)![]() ![]() ![]() You can put this solution on YOUR website! Always be careful and define the variables you are using. \n" ); document.write( "Let x = the speed of the first car \n" ); document.write( "Then x+10 = the speed of the second car \n" ); document.write( "Let t1 = the time the first car takes to travel 120 miles \n" ); document.write( "Then t2 = the time the second car takes to travel 120 miles \n" ); document.write( "We know that t1 = t2 + 1 (why?)\r \n" ); document.write( "\n" ); document.write( "The equation for time of travel is \n" ); document.write( " t = distance / speed\r \n" ); document.write( "\n" ); document.write( "For the two cars we have the following equations\r \n" ); document.write( "\n" ); document.write( " t1 = 120 / x \n" ); document.write( " t2 = 120 (x+10) \n" ); document.write( "Using t1 = t2 +1 we combine the two equations to \n" ); document.write( " \n" ); document.write( "This is solved by the following steps \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " [multiply first term on right by (x+10) and second term on right by \n" ); document.write( " x to get a common denominator] \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "This is most easily solved by factoring. The factors are numbers that multiply to -1200 and add up to 10. Numbers that satisfy these criteria are 40 and -30. \n" ); document.write( "So the equation becomes \n" ); document.write( " \n" ); document.write( "which is true for x = -40 and x = 30. (why?) \n" ); document.write( "You cannot have a speed of -40. So x = 30. \n" ); document.write( "The speed of the first car is 30 miles/hr. \n" ); document.write( "The speed of the second car is 40 miles/hr. \n" ); document.write( "****Checking gives: the first car travels for 120/30 = 4 hours. \n" ); document.write( " the second car travels for 120/40 = 3 hours. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |