document.write( "Question 5211: I've been working on word problems, but this one has me stumped.
\n" ); document.write( "A car travels 120 miles. A second car; traveling 10 mph faster than the first car, makes the same trip in one hour less time. Find the speed of each car.
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Algebra.Com's Answer #3274 by glabow(165)\"\" \"About 
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Always be careful and define the variables you are using.
\n" ); document.write( "Let x = the speed of the first car
\n" ); document.write( "Then x+10 = the speed of the second car
\n" ); document.write( "Let t1 = the time the first car takes to travel 120 miles
\n" ); document.write( "Then t2 = the time the second car takes to travel 120 miles
\n" ); document.write( "We know that t1 = t2 + 1 (why?)\r
\n" ); document.write( "\n" ); document.write( "The equation for time of travel is
\n" ); document.write( " t = distance / speed\r
\n" ); document.write( "\n" ); document.write( "For the two cars we have the following equations\r
\n" ); document.write( "\n" ); document.write( " t1 = 120 / x
\n" ); document.write( " t2 = 120 (x+10)
\n" ); document.write( "Using t1 = t2 +1 we combine the two equations to
\n" ); document.write( " \"+120+%2F+%28x%2B10%29+%2B+1+=+120+%2F+x+\"
\n" ); document.write( "This is solved by the following steps
\n" ); document.write( " \"+1+=+%28120+%2F+x%29+-+%28+120+%2F+%28x%2B10%29+%29\" [rearranging terms]
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\n" ); document.write( " [multiply first term on right by (x+10) and second term on right by
\n" ); document.write( " x to get a common denominator]
\n" ); document.write( " \"+1+=+%28120x+%2B+1200+-+120x%29+%2F+x%28x%2B10%29+\" [simplify and do subtraction]
\n" ); document.write( " \"+x%28x%2B10%29+=+1200+\" [simplify and rearrange]
\n" ); document.write( " \"+x%5E2+%2B+10x+-+1200+=+0+\" [simplify and rearrange]
\n" ); document.write( "This is most easily solved by factoring. The factors are numbers that multiply to -1200 and add up to 10. Numbers that satisfy these criteria are 40 and -30.
\n" ); document.write( "So the equation becomes
\n" ); document.write( " \"+%28x%2B40%29+%28x-30%29+=+0+\"
\n" ); document.write( "which is true for x = -40 and x = 30. (why?)
\n" ); document.write( "You cannot have a speed of -40. So x = 30.
\n" ); document.write( "The speed of the first car is 30 miles/hr.
\n" ); document.write( "The speed of the second car is 40 miles/hr.
\n" ); document.write( "****Checking gives: the first car travels for 120/30 = 4 hours.
\n" ); document.write( " the second car travels for 120/40 = 3 hours.
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