document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=477799>Question 477799</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a number is 3 less than 4 times another number.if their sum is equal to117,then the greater number is\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #327396 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=327396\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x & y be the two numbers\r<BR>\n" );
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document.write( "x= 4y-3<BR>\n" );
document.write( "x-4y=-3............1\r<BR>\n" );
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document.write( "x+y=117.............2\r<BR>\n" );
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document.write( "Multiply (2) by 4 and add the equation to (1)\r<BR>\n" );
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document.write( "4x+4y=468<BR>\n" );
document.write( "x-4y=-3\r<BR>\n" );
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document.write( "5x=465<BR>\n" );
document.write( "x= 465/5<BR>\n" );
document.write( "x=93 <BR>\n" );
document.write( "x= 4y-3<BR>\n" );
document.write( "x+3=4y<BR>\n" );
document.write( "93+3=4y<BR>\n" );
document.write( "96=4y<BR>\n" );
document.write( "y=24  </SPAN>\n" );
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