document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=477668>Question 477668</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let C and D be independent events such that P(C)=0.35 abd P(D)=0.55. Find the following probabilities.\r<BR>\n" );
document.write( "\n" );
document.write( "   A.) P(C and D)\r<BR>\n" );
document.write( "\n" );
document.write( "   B.) P(D or C)\r<BR>\n" );
document.write( "\n" );
document.write( "   C.) P(C and D^c)\r<BR>\n" );
document.write( "\n" );
document.write( "   D.) P(C or D)^C </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #327357 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=327357\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A) P(C and D) = P(C)*P(D) = 0.35*0.55 = 0.1925\r<BR>\n" );
document.write( "\n" );
document.write( "B)P(D or C) = P(D) + P(C) - P(C and D) = 0.55 + 0.35 - 0.1925 = 0.7075\r<BR>\n" );
document.write( "\n" );
document.write( "C) P(C) = P(C and D) + P(C and D') ==> 0.35 = 0.1925 + P(C and D')\r<BR>\n" );
document.write( "\n" );
document.write( "==> P(C and D') = 0.1575.\r<BR>\n" );
document.write( "\n" );
document.write( "D) P((C or D)') = 1 - P(C or D) = 1 - 0.7075 = 0.2925. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );