document.write( "Question 477701: Two vertices of an equilateral triangle are (4,0) and (-6,0). find the coordinates of the point(s) that represent the 3rd vertex. \n" ); document.write( "
Algebra.Com's Answer #327352 by Mathmama(2)\"\" \"About 
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First in an equilateral triangle all the sides are the same length\r
\n" ); document.write( "\n" ); document.write( "Let's call the triangle ABC where A(4,0) B(-6,0) and C (x,y)\r
\n" ); document.write( "\n" ); document.write( "the sides of the triangle are AB, BC and AC
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\n" ); document.write( "To find the length of a side of the Triangle we need to use the formula to calculate the distance between two points (x1, y1) and (x2, y2)\r
\n" ); document.write( "\n" ); document.write( " Distance = \"sqrt%28%28x%5B1%5D+-x%5B2%5D%29%5E2++%2B+%28y%5B1%5D+-+y%5B2%5D%29%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Distance AB = \"sqrt%28%284+-+%28-6%29%29%5E2+%2B+%280+-+0%29%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( " = \"sqrt%28%284+%2B+6%29%5E2%29+%2B+0%29\"\r
\n" ); document.write( "\n" ); document.write( " =\"sqrt%2810%5E2%29\" = 10\r
\n" ); document.write( "\n" ); document.write( "Since all sides are equal then length of BC = 10 and length of AC is also 10\r
\n" ); document.write( "\n" ); document.write( "Distance BC = \"sqrt%28%28-6-x%29%5E2%2B%280+-+y%29%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( " = \"sqrt%28%28-6-x%29%5E2+%2B+y%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Distance AC = \"sqrt%28%284-x%29%5E2%2B%280+-+y%29%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( " = \"sqrt%28%284-x%29%5E2+%2B+y%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "BC = AC
\n" ); document.write( "\"sqrt%28%28-6-x%29%5E2+%2B+y%5E2%29\" = \"sqrt%28%284-x%29%5E2+%2B+y%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "If we square both sides\r
\n" ); document.write( "\n" ); document.write( "\"%28-6-x%29%5E2+%2B+y%5E2\" = \"%284-x%29%5E2+%2B+y%5E2\"\r
\n" ); document.write( "\n" ); document.write( "Subtract \"y%5E2\" from both sides \r
\n" ); document.write( "\n" ); document.write( " \"%28-6-x%29%5E2+\" = \"%284-x%29%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "Expand\r
\n" ); document.write( "\n" ); document.write( "\"36+%2B+12x+%2B+x%5E2+++=++16+-+8x+%2B+x%5E2\"\r
\n" ); document.write( "\n" ); document.write( "Subtract \"x%5E2\" from both sides
\n" ); document.write( "\"36+%2B+12x++++=++16+-+8x+\"\r
\n" ); document.write( "\n" ); document.write( "Add 8x to both sides and subtract 36 from both sides\r
\n" ); document.write( "\n" ); document.write( "36 + 12x = 16 - 8x
\n" ); document.write( "-36 +8x -36 + 8x\r
\n" ); document.write( "\n" ); document.write( "20x = - 20\r
\n" ); document.write( "\n" ); document.write( "Divide both sides by 20\r
\n" ); document.write( "\n" ); document.write( " x = -1\r
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\n" ); document.write( "\n" ); document.write( "So the x-coordinate is -1\r
\n" ); document.write( "\n" ); document.write( "Using the formula for length of BC and plugging in the x-coordinate -1\r
\n" ); document.write( "\n" ); document.write( "Distance BC = \"sqrt%28%28-6-x%29%5E2+%2B+y%5E2%29\" = 10\r
\n" ); document.write( "\n" ); document.write( " \"sqrt%28%28-6-%28-1%29%29%5E2+%2B+y%5E2%29\" = 10\r
\n" ); document.write( "\n" ); document.write( " \"sqrt%28%28-6+%2B+1%29%5E2+%2B+y%5E2%29\" = 10
\n" ); document.write( " \"sqrt%28%28-5%29%5E2+%2B+y%5E2%29\" = 10
\n" ); document.write( " \"sqrt%2825+%2B+y%5E2%29\" = 10
\n" ); document.write( "Square both sides
\n" ); document.write( " \"%2825+%2B+y%5E2%29\" = 100\r
\n" ); document.write( "\n" ); document.write( " Subtract 25 from both sides
\n" ); document.write( " \"y%5E2\" = 75
\n" ); document.write( " Take square root of both sides\r
\n" ); document.write( "\n" ); document.write( " y = +\"sqrt%2875%29\" or y = -\"sqrt%2875%29\"\r
\n" ); document.write( "\n" ); document.write( " y = +\"5sqrt%283%29\" or y = -\"5sqrt%283%29\"\r
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\n" ); document.write( "\n" ); document.write( "The possible coordinates of the third vertex are (-1, +5\"sqrt%283%29\") and (-1, -5\"sqrt%283%29\")
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