document.write( "Question 477607: Please help me with those problems. Thanks a lot!!!
\n" ); document.write( "Multiplication is commutative because x*y = y *x for all x and y. Multiplication is associative
\n" ); document.write( "because x *(y *z) = (x *y) *z. The identity of multiplication is 1, because x*1 = x for all x.
\n" ); document.write( "Let a & b = a + ab + b for all a and b.
\n" ); document.write( "(a) Is the operation & commutative?
\n" ); document.write( "(b) Is the operation & associative?
\n" ); document.write( "(c) What number is the identity of &?
\n" ); document.write( "(d) What number is the inverse of 3 with respect to &? (Recall that the inverse of 3 with
\n" ); document.write( "respect to multiplication is 1/3 because 3 * 1/3 equals the identity of multiplication.)
\n" ); document.write( "Thank you very much for your help!!!! I appreciate it a lot!!!!!!! Thanks!!!
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Algebra.Com's Answer #327314 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Apply the commutative properties of Addition and Multiplication to the RHS of the second equation:\r
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\n" ); document.write( "\n" ); document.write( "So, yes the operation \"\" is commutative \r
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\n" ); document.write( "\n" ); document.write( "You only get one problem per post. Send me a note and I'll give you a quote for the other three problems.\r
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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