document.write( "Question 477578: Joe has a collection of nickles and dimes worth $6.20. If the number of dimes was doubled and the number of nickles was decreased by 37, the value of the coins would be $8.85. How many nickles and dimes does he have? \n" ); document.write( "

Algebra.Com's Answer #327310 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "Let x and y represent the number of nickels and dimes respectively
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document.write( "Question states***CENTS makes sense
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document.write( "  5x + 10y = 620
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document.write( "5(x-7) + 10(2y) = 885\r
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document.write( "  5x + 10y = 620
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document.write( "  5x + 10(2y) = 920\r
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document.write( "  -5x - 10y = -620
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document.write( "   5x + 10(2y) = 920
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document.write( "           10y = 300
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document.write( "             y = 30, the number of dimes. Number of nickels is 64.\r
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document.write( "CHECKING our Answer***
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document.write( "5(x-7) + 10(2y) = 885
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document.write( "5*57 + 10*60 = 285 + 600 = 885 OR $8.85 \n" );
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