document.write( "Question 477401: FACTOR the trinomial completely x^2 +6x-16 \n" ); document.write( "
Algebra.Com's Answer #327226 by Edwin McCravy(20055)\"\" \"About 
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document.write( "x² + 6x - 16\r\n" );
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document.write( "Think of two integers which multiply to give 16 yet subtract to give 6\r\n" );
document.write( "They are 8 and 2, because 8×2 = 16 and 8-2=6, so write this first without\r\n" );
document.write( "signs:\r\n" );
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document.write( "(x   8)(x   2)\r\n" );
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document.write( "Then to make the 8 and the 2 multiply to give the last term of the \r\n" );
document.write( "original-16, you have to give one of them a + sign and the other a\r\n" );
document.write( "- sign.  So it's either\r\n" );
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document.write( "(x - 8)(x + 2) or (x + 8)(x - 2)\r\n" );
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document.write( "FOIL them both out and you'll see that the first one gives x² - 6x - 16,\r\n" );
document.write( "which is not the original, but when you FOIL out the second one you get\r\n" );
document.write( "x² + 6x - 16, which is the original.\r\n" );
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document.write( "So the answer is\r\n" );
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document.write( "(x + 8)(x - 2)\r\n" );
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document.write( "Edwin
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