document.write( "Question 477301: Find three consecutive odd whole numbers such that the sum of the squares of the two smaller numners is 9 more than the square of the largest. \n" ); document.write( "
Algebra.Com's Answer #327191 by robertb(5830)\"\" \"About 
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\"x%5E2+%2B+%28x%2B2%29%5E2+=+%28x%2B4%29%5E2+%2B+9\"
\n" ); document.write( "==> \"x%5E2+%2B+x%5E2+%2B+4x+%2B+4+=+x%5E2+%2B+8x+%2B+16+%2B+9\"\r
\n" ); document.write( "\n" ); document.write( "==> \"x%5E2+-+4x+-+21+=+0\"\r
\n" ); document.write( "\n" ); document.write( "<==> (x - 7 )(x + 3 ) = 0 ==> x = 7, -3.
\n" ); document.write( "Eliminate -3 because it is not non-negative.\r
\n" ); document.write( "\n" ); document.write( "==> the numbers are 7,9, 11.
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