document.write( "Question 477121: Ok here is the problem.
\n" ); document.write( "An airplane flying at a rate of 500 miles per hour leaves Los Angeles.One-half hour later,a second airplane leaves Los Angeles in the same direction flying at a rate of 600 miles per hour.How long will it take the second airplane to overtake the first? \n" ); document.write( "
Algebra.Com's Answer #327178 by ankor@dixie-net.com(22740)\"\" \"About 
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An airplane flying at a rate of 500 miles per hour leaves Los Angeles.
\n" ); document.write( "One-half hour later,a second airplane leaves Los Angeles in the same direction flying at a rate of 600 miles per hour.
\n" ); document.write( "How long will it take the second airplane to overtake the first?
\n" ); document.write( ":
\n" ); document.write( "Let t = the travel time of the 2nd airplane (faster)
\n" ); document.write( "then
\n" ); document.write( "(t+.5) = the travel time of the 1st airplane
\n" ); document.write( ":
\n" ); document.write( "When the 2nd plane catches up with the 1st they will have traveled the same distance.
\n" ); document.write( "Write dist equation: dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "Fast plane dist = slower plane dist
\n" ); document.write( "600t = 500(t+.5)
\n" ); document.write( "600t = 500t + 250
\n" ); document.write( "600t - 500t = 250
\n" ); document.write( "100t = 250
\n" ); document.write( "t = \"250%2F100\"
\n" ); document.write( "t = 2.5 hrs for the faster plane to catch the slower
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this by finding the dist each traveled, they should be equal
\n" ); document.write( "600*2.5 = 1500 mi
\n" ); document.write( "500(2.5+.5) = 1500 mi \n" ); document.write( "
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