document.write( "Question 477275: Ellen wishes to mix candy worth $1.15 per pound with candy worth $2.87 per pound to form 20 pounds of a mixture worth $1.58 per pound. How many pounds of the more expensive candy should she use? \n" ); document.write( "
Algebra.Com's Answer #327173 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Ellen wishes to mix candy worth $1.15 per pound with candy worth $2.87 per pound to form 20 pounds of a mixture worth $1.58 per pound. How many pounds of the more expensive candy should she use? \n" ); document.write( "---------- \n" ); document.write( "Quantity Eq::: c + e = 20 lbs. \n" ); document.write( "Value Eq:: 115c +287e= 158*20 cents \n" ); document.write( "======================================== \n" ); document.write( "Multiply thru the Quantity equation by 115: \n" ); document.write( "115c + 115e = 115*20 \n" ); document.write( "115c + 287e = 158*20 \n" ); document.write( "--------------------------- \n" ); document.write( "Subtract and solve for \"e\": \n" ); document.write( "172e = 43*20 \n" ); document.write( "Amount of expensive candey needed = 5 lbs. \n" ); document.write( "======================= \n" ); document.write( "cheers, \n" ); document.write( "Stan H. \n" ); document.write( "========== \n" ); document.write( " |