document.write( "Question 477122: Suppose that the width of a rectangle is 5inches shorter than the length and that the perimeter of the rectangle is 50 inches. The formula for the perimeter of a rectangle is p=2L+2W. set up an equation invlving L, the length if the rectangle and slove this linear equation algebricallt to find the lenght and width. \n" ); document.write( "
Algebra.Com's Answer #327168 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Suppose that the width of a rectangle is 5 inches shorter than the length and that the perimeter of the rectangle is 50 inches.
\n" ); document.write( ":
\n" ); document.write( "2L + 2W = 50
\n" ); document.write( "Simplify, divide by 2
\n" ); document.write( "L + W = 25
\n" ); document.write( ":
\n" ); document.write( "\"the width of a rectangle is 5 inches shorter than the length\"
\n" ); document.write( "W = L - 5
\n" ); document.write( ":
\n" ); document.write( "Replace W with (L-5) in the simplified equation
\n" ); document.write( "L + (L-5) = 25
\n" ); document.write( "2L = 25 + 5
\n" ); document.write( "2L = 30
\n" ); document.write( "L = 15 inches is the Length
\n" ); document.write( "then. obviously
\n" ); document.write( "15 - 5 = 10 in is the width
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check by finding the perimeter
\n" ); document.write( "2(15) + 2(10) = 50
\n" ); document.write( " \n" ); document.write( "
\n" );