document.write( "Question 477247: 3x squared=39....solve by using square root property \n" ); document.write( "
Algebra.Com's Answer #327154 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"3x%5E2=39\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=%2839%29%2F%283%29\" Divide both sides by \"3\".\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=13\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%22%22%2B-sqrt%2813%29\" Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x=sqrt%2813%29\" or \"x=-sqrt%2813%29\" Break up the \"plus/minus\" to form two equations.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=sqrt%2813%29\" or \"x=-sqrt%2813%29\".
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