document.write( "Question 477135: 2x + 2>= 5x+ 11, then x \r
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document.write( "a. x<= -3
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document.write( "b. x >= 12
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document.write( "c. x >= -3
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document.write( "d. x>= 3 \n" );
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Algebra.Com's Answer #327079 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 2x + 2>= 5x+ 11, then x \n" ); document.write( "--- \n" ); document.write( "Subtract 2x from both sides: \n" ); document.write( "Subtract 11 from both sides: \n" ); document.write( "-9 >= 3x \n" ); document.write( "x <= -3 \n" ); document.write( "------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=================== \n" ); document.write( "a. x<= -3 \n" ); document.write( "b. x >= 12 \n" ); document.write( "c. x >= -3 \n" ); document.write( "d. x>= 3 \n" ); document.write( " \n" ); document.write( " |