document.write( "Question 477135: 2x + 2>= 5x+ 11, then x \r
\n" ); document.write( "\n" ); document.write( "a. x<= -3
\n" ); document.write( "b. x >= 12
\n" ); document.write( "c. x >= -3
\n" ); document.write( "d. x>= 3
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Algebra.Com's Answer #327079 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
2x + 2>= 5x+ 11, then x
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\n" ); document.write( "Subtract 2x from both sides:
\n" ); document.write( "Subtract 11 from both sides:
\n" ); document.write( "-9 >= 3x
\n" ); document.write( "x <= -3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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\n" ); document.write( "a. x<= -3
\n" ); document.write( "b. x >= 12
\n" ); document.write( "c. x >= -3
\n" ); document.write( "d. x>= 3
\n" ); document.write( "
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