document.write( "Question 49238: Find the slope of the ling PQ.
\n" ); document.write( "P is (13,2) and Q is (-5,26)\r
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\n" ); document.write( "\n" ); document.write( "Write the equation of the line through the points P and Q in the form of y=mx+b.
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Algebra.Com's Answer #32705 by Osran_Shri(18)\"\" \"About 
You can put this solution on YOUR website!
Point P ( x=13, y=2) Point Q ( x1= -5, y1 = 26)\r
\n" ); document.write( "\n" ); document.write( "In y = mx + b equation Slope of Line PQ is :\r
\n" ); document.write( "\n" ); document.write( "m = Delta ( Y ) / Delta (x)
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\n" ); document.write( "m = (y1 - y)/(x1-x) = (26-2) / (-5-13) = -(24/18)= -1.3333 ( Note : negative slope )\r
\n" ); document.write( "\n" ); document.write( "Therefore Slope m = -1.333\r
\n" ); document.write( "\n" ); document.write( "Now Constant b = Y intercept i.e., Point where line PQ crosses Y axis at x=0\r
\n" ); document.write( "\n" ); document.write( "y = mx +b
\n" ); document.write( "b = y - mx = y1-mx1
\n" ); document.write( "b = 2 - (-1.333)(13) = 2 + 17.329 = 19.329 = 19.33( rounded off to 2 digits after decimal point)\r
\n" ); document.write( "\n" ); document.write( "Therefore : Foa a line PQ : Slope m = -1.333 and b = 19.33\r
\n" ); document.write( "\n" ); document.write( "Now Equation can be written in standard format as below :\r
\n" ); document.write( "\n" ); document.write( "y = mx + b \r
\n" ); document.write( "\n" ); document.write( "y = -1.333x + 19.33\r
\n" ); document.write( "\n" ); document.write( "Thats all...
\n" ); document.write( "B.Shridhar\r
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