document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=477047>Question 477047</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi you all I really need help with this question.....Scores on the Standford-Binet I ntelligence scale have a mean of 100 and a standard deviation of 16, and are presuemd to be normally distributed. A person who scores 84 on this scale has what percentile rank within the population? Show all work as to how this is obtained.  I dont even no where to begin or how can someone please help me and direct me with this question please!!!!!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #327047 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=327047\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Scores on the Standford-Binet Intelligence scale have a mean of 100 and a standard deviation of 16, and are presumed to be normally distributed. A person who scores 84 on this scale has what percentile rank within the population?<BR>\n" );
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document.write( "z(84) = (84-100)/16 = -1<BR>\n" );
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document.write( "P(x < 84) = P(z < -1) = 0.1587<BR>\n" );
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document.write( "So 15.87% of the population has a score less than 84.<BR>\n" );
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document.write( "The person has percentile score of 15.87%ile or 16%ile if you found up.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  </SPAN>\n" );
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