document.write( "Question 476992: if MOD (Z-3)=3 THEN PROVE (Z-6)/Z=itan(argZ) \n" ); document.write( "
Algebra.Com's Answer #327027 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
There's a little problem with your statement:\r
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\n" ); document.write( "\n" ); document.write( "Let z = a + bi. \r
\n" ); document.write( "\n" ); document.write( "Then z - 3 = (a- 3) + bi.
\n" ); document.write( "==> |z - 3| = |(a- 3) + bi| = \"sqrt%28%28a-3%29%5E2+%2B+b%5E2%29\" = 3, by the given.\r
\n" ); document.write( "\n" ); document.write( "==> \"%28a-3%29%5E2+%2B+b%5E2+=+3%5E2\"
\n" ); document.write( "==> \"a%5E2+-+6a+%2B+9+%2B+b%5E2+=+9\" ==> \"a%5E2+%2B+b%5E2+=+6a\".\r
\n" ); document.write( "\n" ); document.write( "Now \r
\n" ); document.write( "\n" ); document.write( "=\r
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\n" ); document.write( "\n" ); document.write( "Now \"arg%28z%29+=+tan%5E%28-1%29%28b%2Fa%29\", which gives \"tan%28arg%28z%29%29+=+b%2Fa\", or
\n" ); document.write( "\"b+=+a%2Atan%28arg%28z%29%29\", hence
\n" ); document.write( "\"%28z-6%29%2Fz+=+a%2Ai%2Atan%28arg%28z%29%29+=+Re%28z%29%2Ai%2Atan%28arg%28z%29%29\".
\n" ); document.write( "Check again the statement of your result.
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