document.write( "Question 476981: Let f (x) = 2x^2 + 8x-1\r
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document.write( "(a) Find the derivative f ’ of f. \r
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document.write( "(b) Find an equation of the tangent line to the point of (1,3). \r
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document.write( "(c) Determine whether the critical point gives maximum or minimum f value and find the value. \r
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document.write( "Do appreciate your help. Thanking you in advance \n" );
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Algebra.Com's Answer #327023 by robertb(5830)![]() ![]() You can put this solution on YOUR website! (a) f'(x) = 4x+8\r \n" ); document.write( "\n" ); document.write( "(b) (1,3) is NOT a point on the parabola. \r \n" ); document.write( "\n" ); document.write( "(c) You don't need calculus to know if there is a max or a min, it's obvious from the coefficient of \n" ); document.write( "\n" ); document.write( "BUT if you insist, then f'(x) = 4x+8 = 0 ==> x = -2.\r \n" ); document.write( "\n" ); document.write( "The 2nd derivative is f\"(x) = 4 > 0, so by the 2nd derivative test there is (absolute) min at x = -2. (x = -2 could have been gotten using the good ol' formula |