document.write( "Question 476963: A coffee powder manufacturer works out the variable cost of each kilogram of coffee powder is $2.50 with a fixed cost of $30. He sells it to his distributors at price of $3 per kilogram.\r
\n" ); document.write( "\n" ); document.write( "a) If the amount of coffee powder is x kg,in the answer sheet, write the cost function (C) and the revenue (R) for the manufacturer.\r
\n" ); document.write( "\n" ); document.write( "b)What is the breakeven point for the manufacturer? \n" ); document.write( "
Algebra.Com's Answer #327002 by Theo(13342)\"\" \"About 
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x = number of units sold
\n" ); document.write( "cost is equal to 30 + 2.50x
\n" ); document.write( "sale price is 3x
\n" ); document.write( "c = 2.50x + 30
\n" ); document.write( "r = 3x
\n" ); document.write( "break even point is when the cost function equals the revenue function.
\n" ); document.write( "2.5x + 30 = 3x
\n" ); document.write( "subtract 2.5x from both sides of this equation to get:
\n" ); document.write( "3x - 2.5x = 30 which becomes:
\n" ); document.write( ".5x = 30
\n" ); document.write( "divide both sides of this equation by .5 to get:
\n" ); document.write( "x = 60
\n" ); document.write( "that's the break even point.
\n" ); document.write( "cost = 2.5*60 + 30 = 180
\n" ); document.write( "revenue = 3*60 = 180
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