document.write( "Question 49301: I really have no clue where this is supposed to be section wise\r
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\n" ); document.write( "\n" ); document.write( "Its from my geometery summer work but its an algebra review
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Algebra.Com's Answer #32691 by venugopalramana(3286)\"\" \"About 
You can put this solution on YOUR website!
I really have no clue where this is supposed to be section wise\r
\n" ); document.write( "\n" ); document.write( "-8<=1-3X<10
\n" ); document.write( "TAKE FIRST
\n" ); document.write( "-8<=1-3X
\n" ); document.write( "3X<=1+8=9
\n" ); document.write( "X<=9/3=3
\n" ); document.write( "HENCE X<=3....................FROM I INEQUALITY.
\n" ); document.write( "TAKE NEXT
\n" ); document.write( "1-3X<10
\n" ); document.write( "-3X<10-1=9
\n" ); document.write( "-X<9/3=3
\n" ); document.write( "X>-3
\n" ); document.write( "HENCE X>-3 FROM II INEQUALITY...COMBINING IT EANS
\n" ); document.write( "-3\n" ); document.write( "
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