document.write( "Question 476690: the half life of carbon -14 is 5730
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document.write( "how much of 10 mg sample will remain after 4500 years \n" );
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Algebra.Com's Answer #326888 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! the half life of carbon -14 is 5730 \n" ); document.write( "how much of 10 mg sample will remain after 4500 years \n" ); document.write( ": \n" ); document.write( "The half-life decay formula: \n" ); document.write( "A = Ao*2^(-t/h) \n" ); document.write( "Where \n" ); document.write( "A = resulting amt after t \n" ); document.write( "Ao = initial amt (t=0) \n" ); document.write( "t = time of decay \n" ); document.write( "h = half-life of substance \n" ); document.write( ": \n" ); document.write( "A = 10*2^(-4500/5730) \n" ); document.write( "Find 2^(-4500/5730) \n" ); document.write( "A = 10*.58021 \n" ); document.write( "A = 5.8021 mg after 4500 yrs \n" ); document.write( " |