document.write( "Question 476690: the half life of carbon -14 is 5730
\n" ); document.write( "how much of 10 mg sample will remain after 4500 years
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Algebra.Com's Answer #326888 by ankor@dixie-net.com(22740)\"\" \"About 
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the half life of carbon -14 is 5730
\n" ); document.write( "how much of 10 mg sample will remain after 4500 years
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\n" ); document.write( "The half-life decay formula:
\n" ); document.write( "A = Ao*2^(-t/h)
\n" ); document.write( "Where
\n" ); document.write( "A = resulting amt after t
\n" ); document.write( "Ao = initial amt (t=0)
\n" ); document.write( "t = time of decay
\n" ); document.write( "h = half-life of substance
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\n" ); document.write( "A = 10*2^(-4500/5730)
\n" ); document.write( "Find 2^(-4500/5730)
\n" ); document.write( "A = 10*.58021
\n" ); document.write( "A = 5.8021 mg after 4500 yrs
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