document.write( "Question 476615: Find the solution of the equation on the interval [0,2pi]\r
\n" ); document.write( "\n" ); document.write( "sin 2(theta) + sin (theta) = 0
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Algebra.Com's Answer #326885 by lwsshak3(11628)\"\" \"About 
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Find the solution of the equation on the interval [0,2pi]
\n" ); document.write( "sin 2(theta) + sin (theta) = 0
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\n" ); document.write( "sin2x+sinx=0
\n" ); document.write( "2sinxcosx+sinx=0
\n" ); document.write( "sinx(2cosx+1)=0
\n" ); document.write( "sinx=0
\n" ); document.write( "x=0
\n" ); document.write( "..
\n" ); document.write( "2cosx+1=0
\n" ); document.write( "2cosx=-1
\n" ); document.write( "cosx=-1/2
\n" ); document.write( "x=2π/3 and 4π/3 (quadrants II and III)
\n" ); document.write( "ans
\n" ); document.write( "theta=0, 2π/3 and 4π/3
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