document.write( "Question 476615: Find the solution of the equation on the interval [0,2pi]\r
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document.write( "sin 2(theta) + sin (theta) = 0 \n" );
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Algebra.Com's Answer #326885 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Find the solution of the equation on the interval [0,2pi] \n" ); document.write( "sin 2(theta) + sin (theta) = 0 \n" ); document.write( "** \n" ); document.write( "sin2x+sinx=0 \n" ); document.write( "2sinxcosx+sinx=0 \n" ); document.write( "sinx(2cosx+1)=0 \n" ); document.write( "sinx=0 \n" ); document.write( "x=0 \n" ); document.write( ".. \n" ); document.write( "2cosx+1=0 \n" ); document.write( "2cosx=-1 \n" ); document.write( "cosx=-1/2 \n" ); document.write( "x=2π/3 and 4π/3 (quadrants II and III) \n" ); document.write( "ans \n" ); document.write( "theta=0, 2π/3 and 4π/3 \n" ); document.write( " |