document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=49270>Question 49270</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the dimentions of a rectangle( a )with the greatest area whose perimeter is 30 feet. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #32686 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=32686\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the dimentions of a rectangle( a )with the greatest area whose perimeter is 30 feet.<BR>\n" );
document.write( "PERIMETER(L+B)2=30<BR>\n" );
document.write( "L+B=15<BR>\n" );
document.write( "AREA = LB=L(15-L)<BR>\n" );
document.write( "A=-(L^2-15L)=-[L^2-2(L)(7.5)+7.5^2-7.5^2]=7.5^2-(L-7.5)^2<BR>\n" );
document.write( "SINCE (L-7.5)^2 IS ALWAYS GREATER THAN EQUAL TO ZERO,AREA IS MAXIMUM WHEN THIS IS ZERO<BR>\n" );
document.write( "HENCE WHEN L-7.5=0....OR...L=7.5,AREA IS MAXIMIUM AND EQUAL TO 7.5^2<BR>\n" );
document.write( "HENCE L=B=7.5 FOR MAXIMUM AREA </SPAN>\n" );
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