document.write( "Question 476652: using a system of equations to solve the applied problem. Solve the system Ten liters of 30% solution needs to be mixed with 80% solution to produce a 50 % solution. How much of the 80% solution is needed. I need this by 2pm
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Algebra.Com's Answer #326847 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Ten liters of 30% solution needs to be mixed with 80% solution to produce a 50 % solution.
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\n" ); document.write( "Let x = amt of 80% solution
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\n" ); document.write( "you can solve this with a single equation using the decimal equiv of per cent;
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\n" ); document.write( ".30(10) + .80x = .50(x + 10)
\n" ); document.write( "3 + .80x = .50x + 5
\n" ); document.write( ".80x - .50x = 5 - 3
\n" ); document.write( ".30x = 2
\n" ); document.write( "x = $\"2%2F.3\"$
\n" ); document.write( "x = 6 $\"2%2F3\"$ liters of 80% solution required
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\n" ); document.write( "Check this decimals
\n" ); document.write( ".3(10) + .8(6.67) = .50(6.67+10)
\n" ); document.write( "3 + 5.333 = .50(16.67)
\n" ); document.write( "8.333 ~ 8.335
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