document.write( "Question 476630: \"if (2^k)-1 is a prime number then, prove that (2^(k-1))(2^k-1)is a perfect number.\"
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document.write( "(i know it is the definition but i want proof) \n" );
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Algebra.Com's Answer #326822 by MathLover1(20849)![]() ![]() You can put this solution on YOUR website! Theorem: \n" ); document.write( " If \n" ); document.write( "\n" ); document.write( "Proof: \r \n" ); document.write( "\n" ); document.write( "Suppose first that \n" ); document.write( "\n" ); document.write( "To show \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This shows that \n" ); document.write( "\n" ); document.write( " On the other hand, \n" ); document.write( "\n" ); document.write( "Again sigma is multiplicative so\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Together these two criteria give\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so, \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now substitute this back into the equation above and \n" ); document.write( "\n" ); document.write( "Since \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so \n" ); document.write( "\n" ); document.write( "This means that \n" ); document.write( "\n" ); document.write( "Thus \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |