document.write( "Question 476439: A student inherited $5000. She invested part of it at 10% and the rest at 8%. If her
\n" ); document.write( "total interest amounted to $460, how much did she invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #326778 by mananth(16946)\"\" \"About 
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Investment I 10.00% per annum
\n" ); document.write( "Investment II 8.00% per annum
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\n" ); document.write( "x + y 5000 ------------------------1
\n" ); document.write( "10.00% x + 8.00% y = $460.00
\n" ); document.write( "Multiply by 100
\n" ); document.write( "10 x + 8 y = $46,000.00 --------2
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\n" ); document.write( "Multiply (1) by -10
\n" ); document.write( "we get
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\n" ); document.write( "-10 x -10 y = -50000.00
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\n" ); document.write( "Add this to (2)
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\n" ); document.write( "0 x -2 y = -$4,000.00
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\n" ); document.write( "divide by -2
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\n" ); document.write( "y = $2,000.00 investment at 8.00%
\n" ); document.write( "Balance $3,000.00 investment at 10.00%\r
\n" ); document.write( "\n" ); document.write( "CHECK
\n" ); document.write( "$3,000.00 $300.00
\n" ); document.write( "$2,000.00 $160.00
\n" ); document.write( "Total $460.00
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