document.write( "Question 476428: Assume that women have heights that are normally distributed with a mean of 63.6 inches and a
\n" ); document.write( "standard deviation of 2.5 inches. Find the value of the quartile Q3.
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Algebra.Com's Answer #326769 by robertb(5830)\"\" \"About 
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We need to find \"alpha+=+Q%5B3%5D+\"such that \"P%28+Z+%3C=+alpha%29+=+0.75\"
\n" ); document.write( "From a table of cumulative standard normal values, we get \"P%28+Z+%3C=+0.675%29+=+0.75\"\r
\n" ); document.write( "\n" ); document.write( "==> \"alpha+=+0.675\" ==> \"%28H+-+63.6%29%2F2.5+=+0.675\"\r
\n" ); document.write( "\n" ); document.write( "==> H - 63.6 = 1.6875 ==> H = 65.2875, the 3rd quartile.
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