document.write( "Question 476570: my tens digit is 3 more than my ones. my hundred digit is 2 less than my tens. im an odd number.\r
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Algebra.Com's Answer #326763 by josmiceli(19441)\"\" \"About 
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Let \"n\" = one's digit
\n" ); document.write( "The number is:
\n" ); document.write( "\"+n+%2B+10%2A%28n+%2B+3%29+%2B+100%2A%28n+%2B+3+-+2%29+\"
\n" ); document.write( "\"+n+%2B+10n+%2B+30+%2B+100n+%2B+100+\"
\n" ); document.write( "\"+111n+%2B+130+\"
\n" ); document.write( "If the number is odd, n can only be 1,3,5,7 or 9
\n" ); document.write( "If \"+n+=+1+\",
\n" ); document.write( "\"+111%2A1+%2B+130+=+241+\"
\n" ); document.write( "If \"+n+=+3+\",
\n" ); document.write( "\"+111%2A3+%2B+130+=+463+\"
\n" ); document.write( "If \"+n+=+5+\",
\n" ); document.write( "\"+111%2A5+%2B+130+=+685+\"
\n" ); document.write( "If \"+n+=+7+\",
\n" ); document.write( "\"+111%2A7+%2B+130+=+907+\" (this fails, since the
\n" ); document.write( "10's digit is not \"+n+%2B+3+\"
\n" ); document.write( "If \"+n+=+9+\",
\n" ); document.write( "\"+111%2A9+%2B+130+=+1129+\" (this fails, it's a 4-digit number)
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