document.write( "Question 476507: A train leaves station 1 at 7:00am for station 2, which is 1080 kilometers away. At 10:00am, a faster train leaves station 2 for station 1 and runs 15kph faster than the first train. When do the trains pass each other if this occurs midway between station 1 and 2? \n" ); document.write( "
Algebra.Com's Answer #326761 by mananth(16946)\"\" \"About 
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Train 1 7.00 AM --- x kph
\n" ); document.write( "Train 2 10.00 AM--- x+15 kph\r
\n" ); document.write( "\n" ); document.write( "Distance between two stations = 1080
\n" ); document.write( "Midway = 540 km\r
\n" ); document.write( "\n" ); document.write( "AT 10.00 AM Train A is 540-3x from A\r
\n" ); document.write( "\n" ); document.write( "Distance between them at 10.00AM = 1080-3x
\n" ); document.write( "combined speed = x+x+15=2x+15 kph\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "From 10:00 AM the time taken for them to meet is the same.
\n" ); document.write( "Time taken by them to meet = Time taken by Train B to meet\r
\n" ); document.write( "\n" ); document.write( "(1080-3x)/(2x+15)= 540/(x+15)
\n" ); document.write( "(x+15)(1080-3x)=540(2x+15)
\n" ); document.write( "1080x-3x^2+16200 -45x= 1080x+8100
\n" ); document.write( "-3x^2-45x+8100=0
\n" ); document.write( "3x^2+45x-8100=0
\n" ); document.write( "Find the roots of the equation by quadratic formula
\n" ); document.write( "a= -3 ,b= -45 ,c= 8100
\n" ); document.write( " b^2-4ac=
\n" ); document.write( "b^2-4ac= 2025 - 97200
\n" ); document.write( "b^2-4ac= 99225
\n" ); document.write( "\"sqrt%28%0999225%09%29\"= 315
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "x1=( 45 + 315 )/ -6
\n" ); document.write( "x1= -60
\n" ); document.write( "x2=( 45 -315 ) / -6
\n" ); document.write( "x2= 45 \r
\n" ); document.write( "\n" ); document.write( "Train 1 speed = 45 kph which is positive\r
\n" ); document.write( "\n" ); document.write( "Train A speed = 45 kph
\n" ); document.write( "Train B speed = 60 kph
\n" ); document.write( "..
\n" ); document.write( "Time taken by train B to meet = 540/60 = 9 hours
\n" ); document.write( "Train B starts at 10:00 AM
\n" ); document.write( "They meet at 10 + 9 = 19:00 hours OR 7:00 PM\r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca\r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca
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