document.write( "Question 49278: Give f(x)=5x^2-3x+1, find f(-2). \n" ); document.write( "
Algebra.Com's Answer #32676 by AnlytcPhil(1810) You can put this solution on YOUR website! Give f(x)=5x^2-3x+1, find f(-2).\r\n" ); document.write( "\r\n" ); document.write( " f(x) = 5x² - 3x + 1\r\n" ); document.write( "\r\n" ); document.write( "Replace all the x's on both sides with empty \r\n" ); document.write( "parentheses:\r\n" ); document.write( "\r\n" ); document.write( "f( ) = 5( )² - 3( ) + 1\r\n" ); document.write( "\r\n" ); document.write( "Now fill in all the empty parentheses with -2\r\n" ); document.write( "\r\n" ); document.write( "f(-2) = 5(-2)² - 3(-2) + 1\r\n" ); document.write( "\r\n" ); document.write( "Leave the left side as it is but simplify the\r\n" ); document.write( "right side:\r\n" ); document.write( "\r\n" ); document.write( "f(-2) = 5(-2)² - 3(-2) + 1\r\n" ); document.write( "f(-2) = 5(4) + 6 + 1\r\n" ); document.write( "f(-2) = 20 + 7\r\n" ); document.write( "f(-2) = 27\r\n" ); document.write( " \r\n" ); document.write( "So you see, functional notation merely amounts\r\n" ); document.write( "to \"plugging in\" for x what's in the parentheses\r\n" ); document.write( "after the \"f\".\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |