document.write( "Question 476519: lnx+ln(x-5)=ln6 \n" ); document.write( "
Algebra.Com's Answer #326747 by lwsshak3(11628)\"\" \"About 
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lnx+ln(x-5)=ln6
\n" ); document.write( "**
\n" ); document.write( "lnx+ln(x-5)-ln6=0
\n" ); document.write( "place under a single log
\n" ); document.write( "ln(x(x-5))/6=0
\n" ); document.write( "convert to exponential form:(base(e) raised to log of number(0)=number(x(x-5))/6
\n" ); document.write( "e^0=(x(x-5))/6=1
\n" ); document.write( "x^2-5x=6
\n" ); document.write( "x^2-5x-6=0
\n" ); document.write( "(x-6)(x+1)=0
\n" ); document.write( "x=6
\n" ); document.write( "or
\n" ); document.write( "x=-1 (reject, x>0)
\n" ); document.write( "Check:
\n" ); document.write( "lnx+ln(x-5)
\n" ); document.write( "ln(6)+ln(1)
\n" ); document.write( "ln(6)+0=ln(6) \n" ); document.write( "
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