document.write( "Question 476522: solve for x\r
\n" ); document.write( "\n" ); document.write( "log3 + log(x+4) = log5 + log(x-3)
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Algebra.Com's Answer #326744 by lwsshak3(11628)\"\" \"About 
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solve for x
\n" ); document.write( "log3 + log(x+4) = log5 + log(x-3)
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\n" ); document.write( "log3 + log(x+4) = log5 + log(x-3)
\n" ); document.write( "log3 + log(x+4) - log5 - log(x-3)=0
\n" ); document.write( "log3 + log(x+4) - (log5 + log(x-3))=0
\n" ); document.write( "place under a single log
\n" ); document.write( "log(3*(x+4))/(5*(x-3)=0
\n" ); document.write( "convert to exponential form: (base(10) raised to log of number(0)=number(3*(x+4))/(5*(x-3)
\n" ); document.write( "10^0=3x+12/5x-15=1
\n" ); document.write( "3x+12=5x-15
\n" ); document.write( "2x=27
\n" ); document.write( "x=27/2=13.5
\n" ); document.write( "Check:
\n" ); document.write( "log3 + log(x+4) = log5 + log(x-3)
\n" ); document.write( "log3 + log(17.5) = log5 + log(10.5)
\n" ); document.write( "1.7202=1.7202
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