document.write( "Question 476522: solve for x\r
\n" );
document.write( "\n" );
document.write( "log3 + log(x+4) = log5 + log(x-3) \n" );
document.write( "
Algebra.Com's Answer #326744 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! solve for x \n" ); document.write( "log3 + log(x+4) = log5 + log(x-3) \n" ); document.write( "** \n" ); document.write( "log3 + log(x+4) = log5 + log(x-3) \n" ); document.write( "log3 + log(x+4) - log5 - log(x-3)=0 \n" ); document.write( "log3 + log(x+4) - (log5 + log(x-3))=0 \n" ); document.write( "place under a single log \n" ); document.write( "log(3*(x+4))/(5*(x-3)=0 \n" ); document.write( "convert to exponential form: (base(10) raised to log of number(0)=number(3*(x+4))/(5*(x-3) \n" ); document.write( "10^0=3x+12/5x-15=1 \n" ); document.write( "3x+12=5x-15 \n" ); document.write( "2x=27 \n" ); document.write( "x=27/2=13.5 \n" ); document.write( "Check: \n" ); document.write( "log3 + log(x+4) = log5 + log(x-3) \n" ); document.write( "log3 + log(17.5) = log5 + log(10.5) \n" ); document.write( "1.7202=1.7202 \n" ); document.write( " |