document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=476553>Question 476553</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Imagine a pole stuck in the ground in such a way that it sticks up perpendicularly and 12 ft of it is showing. Then, all of a sudden the wind knocks the top off and the top touches 4ft from the base. The top is partial attached. How high is the break? i am having trouble setting this problem up </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #326737 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=326737\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = hypotenuse of the right triangle formed.<BR>\n" );
document.write( "Then the perpendicular side of the right triangle will measure 12 - x feet, while the horizontal side will be 4 feet.<BR>\n" );
document.write( "Then by the Pythagorean theorem, \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2812-x%29%5E2+%2B+462+=+x%5E2 ALIGN=MIDDLE  ALT=\"%2812-x%29%5E2+%2B+462+=+x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<==> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=144+-+24x+%2B+x%5E2+%2B+16+=+x%5E2 ALIGN=MIDDLE  ALT=\"144+-+24x+%2B+x%5E2+%2B+16+=+x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "==> 160 = 24x<BR>\n" );
document.write( "==> x = 20/3<BR>\n" );
document.write( "==> the break is up 12 - x = 16/3 feet, or approximately 5.33 feet. </SPAN>\n" );
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