document.write( "Question 476530: A shopper buys 3 oranges and 5 lemons for $10.26, while a second shopper buys 4 lemons and 6 oranges for $11.16. What is the price of each fruit?\r
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document.write( "I got 3x+5y=10.26 and 4x+6y=11.16\r
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document.write( "I gave the answer of x=2.88 y=.324 but i was wrong. \n" );
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Algebra.Com's Answer #326714 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! Here's a hint for future problems: use a letter for the variables that makes sense. In this problem instead of using x and y (easily confused) use O for oranges (that's letter O, not zero) and use L for lemons. Now write your equations. \n" ); document.write( ". \n" ); document.write( "For the three oranges and 5 lemons you get: \n" ); document.write( ". \n" ); document.write( "3*O + 5*L = 10.26 \n" ); document.write( ". \n" ); document.write( "So far, no problem. \n" ); document.write( ". \n" ); document.write( "For the 4 lemons and 6 oranges you get: \n" ); document.write( ". \n" ); document.write( "6*O + 4*L = 11.16 \n" ); document.write( ". \n" ); document.write( "Notice the difference in the second equation. You got the lemons and oranges reversed in order when you wrote 4x + 6y = 11.16. \n" ); document.write( ". \n" ); document.write( "Now you have the two equations: \n" ); document.write( ". \n" ); document.write( "3*O + 5*L = 10.26 \n" ); document.write( "6*O + 4*L = 11.16 \n" ); document.write( ". \n" ); document.write( "Multiply the top equation (both sides and all terms) by 2 to get: \n" ); document.write( ". \n" ); document.write( "6*O + 10*L = 20.52 <--- First equation doubled \n" ); document.write( "6*0 + 4*L = 11.16 <--- Second equation unchanged \n" ); document.write( ". \n" ); document.write( "Now subtract the two equations vertically and the answer becomes: \n" ); document.write( ". \n" ); document.write( " 6*L = 9.36 \n" ); document.write( ". \n" ); document.write( "Solve for the price of lemons by dividing by 6 to get: \n" ); document.write( ". \n" ); document.write( "L = 1.56 \n" ); document.write( ". \n" ); document.write( "Now let's return to the second equation and substitute 1.56 for L. This equation then becomes: \n" ); document.write( ". \n" ); document.write( "6*O + (4*1.56) = 11.16 \n" ); document.write( ". \n" ); document.write( "Multiply the terms in the parentheses and the equation becomes: \n" ); document.write( ". \n" ); document.write( "6*O + 6.24 = 11.16 \n" ); document.write( ". \n" ); document.write( "Subtract 6.24 from both sides and you have: \n" ); document.write( ". \n" ); document.write( "6*O = 4.92 \n" ); document.write( ". \n" ); document.write( "Divide both sides by 6 to get: \n" ); document.write( ". \n" ); document.write( "O = 0.82 \n" ); document.write( ". \n" ); document.write( "So oranges are 82 cents each and lemons are $1.56 each. \n" ); document.write( ". \n" ); document.write( "Hope this helped you out a little bit. You obviously know what you are doing, but just made a simple mistake.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |