document.write( "Question 476521: solve for x\r
\n" ); document.write( "\n" ); document.write( " $\"+log%28+6%2C%282x%2B1%29+%29+-+log+%28+6%2C%28x-5%29+%29+=+0+\"$ \n" ); document.write( "

Algebra.Com's Answer #326710 by robertb(5830) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"log%286%2C%28%282x%2B1%29%2F%28x-5%29%29%29+=+0\"$ by property of logarithms.\r
\n" ); document.write( "\n" ); document.write( " $\"6%5E0+=+1+=%282x%2B1%29%2F%28x-5%29\"$ , the exponential equivalent.\r
\n" ); document.write( "\n" ); document.write( "==> x-5 = 2x+1 ==> x = -6.\r
\n" ); document.write( "\n" ); document.write( "If x = -6 is substituted into the original equation, we get
\n" ); document.write( " $\"log%286%2C%28-11%29%29+-+log%286%2C%28-11%29%29+=+0\"$ , which is false ,
\n" ); document.write( "because both terms at the left-side are undefined.
\n" ); document.write( "Hence the equation has no solution. \n" ); document.write( "

\n" );