document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=476177>Question 476177</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have been working on this equation involving 2 radicals for 2 days. Here is what I have so far.<BR>\n" );
document.write( "radical(3x+1)-1- radical (x+4) = 0<BR>\n" );
document.write( "isolating 1 radical: radical (3x+1)-1 = radical (x+4)<BR>\n" );
document.write( "squaring both sides of the equation: (radical(3x+1)-1)^2 = (radical(x+4))^2<BR>\n" );
document.write( "(3x+1)+ 2 radical(3x+1)+1 = x+4<BR>\n" );
document.write( "2 radical(3x+1) = -2x+2<BR>\n" );
document.write( "squaring both sides again: (2 radical(3x+1))^2 = (-2x+2)^2<BR>\n" );
document.write( "4(9x+1)=4x^2-4x+4<BR>\n" );
document.write( "36x+4= 4x^2-4x+4<BR>\n" );
document.write( "factoring:0=4x^2-40x<BR>\n" );
document.write( "Where do I go from here to get the answer of 5 as a solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #326702 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=326702\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> there is a sign error in the first squaring step\r<BR>\n" );
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document.write( "(3x+1)(-) 2 radical(3x+1)+1 = x+4\r<BR>\n" );
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document.write( "-2 radical(3x+1) = -2x+2 ___ dividing by -2\r<BR>\n" );
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document.write( "radical(3x+1) = x - 1 ___ squaring\r<BR>\n" );
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document.write( "3x + 1 = x^2 - 2x + 1 ___ 0 = x^2 - 5x ___ 0 = x(x - 5) </SPAN>\n" );
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