document.write( "Question 476514: the sum of three numbers is 105. the third is 11 less than ten times the second. twice the first is 7 more than 3 times the second. find the numbers. \n" ); document.write( "
Algebra.Com's Answer #326701 by ankor@dixie-net.com(22740)\"\" \"About 
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the sum of three numbers is 105.
\n" ); document.write( "x + y + z = 105
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\n" ); document.write( "The third is 11 less than ten times the second.
\n" ); document.write( "z = 10y - 11
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\n" ); document.write( "twice the first is 7 more than 3 times the second.
\n" ); document.write( "2x = 3y + 7
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\n" ); document.write( "Multiply the 1st equation by 2
\n" ); document.write( "2x + 2y + 2z = 210
\n" ); document.write( "Replace 2x with (3y+7)
\n" ); document.write( "3y + 7 + 2y + 2z = 210
\n" ); document.write( "5y + 2z = 210 - 7
\n" ); document.write( "5y + 2z = 203
\n" ); document.write( "Replace z with (10y-11)
\n" ); document.write( "5y + 2(10y-11) = 203
\n" ); document.write( "5y + 20y - 22 = 203
\n" ); document.write( "25y = 203 + 22
\n" ); document.write( "25y = 225
\n" ); document.write( "y = \"225%2F25\"
\n" ); document.write( "y = 9
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\n" ); document.write( "z = 10(9) - 11
\n" ); document.write( "z = 79
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\n" ); document.write( "2x = 3(9) + 7
\n" ); document.write( "2x = 34
\n" ); document.write( "x = 17
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\n" ); document.write( "check this
\n" ); document.write( "17 + 9 + 79 = 105 confirms our solutions of x=17, y=9, z=79 \n" ); document.write( "
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