document.write( "Question 476395: A boat travels 30 miles upstream in 5 hours. Going downstream, it can travel 60 miles in the same amount of time. Find the speed of the current and the speed of the boat in still water. \n" ); document.write( "
Algebra.Com's Answer #326668 by ankor@dixie-net.com(22740)\"\" \"About 
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A boat travels 30 miles upstream in 5 hours.
\n" ); document.write( " Going downstream, it can travel 60 miles in the same amount of time.
\n" ); document.write( " Find the speed of the current and the speed of the boat in still water.
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\n" ); document.write( "Let c = speed of the current
\n" ); document.write( "Let s = speed of the boat in still water
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\n" ); document.write( "Write two distance equations: dist = time * speed
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\n" ); document.write( "5(s - c) = 30
\n" ); document.write( "5(s + c) = 60
\n" ); document.write( "Simplify, divide both equations by 5, results
\n" ); document.write( "s - c = 6
\n" ); document.write( "s + c = 12
\n" ); document.write( "--------------addition eliminates c, find s
\n" ); document.write( "2s = 18
\n" ); document.write( "s = \"18%2F2\"
\n" ); document.write( "s = 9 mph in still water
\n" ); document.write( "then
\n" ); document.write( "9 + c = 12
\n" ); document.write( "c = 12 - 9
\n" ); document.write( "c = 3 mph is the speed of the current
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check in both equation
\n" ); document.write( "5(9 - 3) = 30
\n" ); document.write( "5(9 + 3) = 60 \n" ); document.write( "
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