document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=476412>Question 476412</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One canned juice drink is 20% Orange juice; another 10% Orange juice. How many liters of each should be mixed together in order to get 10L that is 13% Orange juice? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #326651 by </B><A HREF=/tutors/aboutme.mpl?userid=ccs2011><B>ccs2011(207)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ccs2011><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ccs2011><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=326651\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let A,B represent the amount of 20% drink and 10% drink.<BR>\n" );
document.write( "A+B = 10<BR>\n" );
document.write( "0.2A + 0.1B = 0.13*10<BR>\n" );
document.write( "Use substitution<BR>\n" );
document.write( "From 1st equation<BR>\n" );
document.write( "A = 10 - B<BR>\n" );
document.write( "Substituting into 2nd equation<BR>\n" );
document.write( "0.2(10-B) + 0.1B = 1.3<BR>\n" );
document.write( "Distribute<BR>\n" );
document.write( "2 - 0.2B +0.1B = 1.3<BR>\n" );
document.write( "Combine like terms<BR>\n" );
document.write( "-0.1B = -0.7<BR>\n" );
document.write( "Divide by -.1 on both sides<BR>\n" );
document.write( "B = 7<BR>\n" );
document.write( "Substituting back into 1st equation<BR>\n" );
document.write( "A = 10 - 7 = 3<BR>\n" );
document.write( "Therefore 3L of 20% drink should be mixed with 7L of 10% drink. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );