document.write( "Question 476308: Dear math teacher,\r
\n" ); document.write( "\n" ); document.write( "I am having difficulties with the following problem:\r
\n" ); document.write( "\n" ); document.write( "4 times nC2 = (n+2)C3, (a)solve for n; (b) n cannot equal to or must be different from ...integers.\r
\n" ); document.write( "\n" ); document.write( "4*n(n-1)*(n-2)!/(n-2)!(2.1) = (n+2)!/(n+2-3)!*(3.2.1) and after canceling out 2(n-2)! we get\r
\n" ); document.write( "\n" ); document.write( "2n(n-1) = (n+2)(n+1)n(n-1)!/(n-1)!(3.2.1) and after canceling out n and (n-1)! we get\r
\n" ); document.write( "\n" ); document.write( "2(n-1) = (n+2)(n+1)/6\r
\n" ); document.write( "\n" ); document.write( "n^2 - 9n + 14 = 0
\n" ); document.write( "(n-7)(n-2) = 0
\n" ); document.write( "n=7 and n=2\r
\n" ); document.write( "\n" ); document.write( "To answer part (a) of the problem, I say the solution is 7 only since (n-2) was canceled out above. For part (b) n cannot equal to 0, 1, and 2 since n canceled out, (n-1) canceled out, and (n-2) term canceled out.\r
\n" ); document.write( "\n" ); document.write( "Please let me know, if I reason through this correctly. Thank you very much.
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Algebra.Com's Answer #326596 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
you calculated the answer correctly.
\n" ); document.write( "n is equal to 7 or n is equal to 2.
\n" ); document.write( "that takes care of part a.
\n" ); document.write( "both of those values of n will make the equations equal.
\n" ); document.write( "that was confirmed.
\n" ); document.write( "part b says n cannot be equal to, or must be different from ... integers?
\n" ); document.write( "not sure i understand that, but, if i must pick a number that should be disallowed, it would be n = 2.
\n" ); document.write( "your equation is:
\n" ); document.write( "4*nC2 = (n+2)C3
\n" ); document.write( "this equation can be translated to:
\n" ); document.write( "(4*n!)/(2!(n-2)!) = (n+2)!/(3!(n+2-3)!) which becomes:
\n" ); document.write( "(4*n!)/(2!(n-2)!) = (n+2)!/(3!(n-1)!)
\n" ); document.write( "when n = 7, this equation becomes:
\n" ); document.write( "4*7!/(2!*5!) = 9!/(3!*6!)
\n" ); document.write( "when n = 2, this equation becomes:
\n" ); document.write( "4*2!/(2!*0!) = 4!/(3!*1!)
\n" ); document.write( "the left side of this equation have n equal to 2 which is equal to the number of positions in the subgroup you are trying to create.
\n" ); document.write( "if that's what they're referring to, then n = 2 would be disallowed because the subgroup is the same size as the group.
\n" ); document.write( "outside of that I'm not exactly sure what their complaint is.
\n" ); document.write( "assuming i understood correctly, i would say that n = 2 would be disallowed because the group created is the same size as the subgroup that would be created from it.\r
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