document.write( "Question 476252: 6. Given the following sets, select the statement below that is NOT true.
\n" ); document.write( "A = {r, i, s, k, e, d}, B = {r, i, s, e}, C = {s, i, r}
\n" ); document.write( " (Points : 2)
\n" ); document.write( " B ⊂ A
\n" ); document.write( " A ⊂ C
\n" ); document.write( " B ⊆ A
\n" ); document.write( " C ⊆ A
\n" ); document.write( " C ⊆ B\r
\n" ); document.write( "\n" ); document.write( "thank you for your help.
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Algebra.Com's Answer #326567 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
Note the difference between \"subset\" and \"proper subset\".
\n" ); document.write( "⊆ and ⊂. Both symbols require that every member of the set
\n" ); document.write( "on the left of the symbol is also a member of the element on
\n" ); document.write( "the right of the symbol. However with ⊂, the set on the left
\n" ); document.write( "cannot contain ALL OF the elements of the set on the right of ⊂.
\n" ); document.write( "IOW, ⊆ and ⊂ are the same EXCEPT when the same set is on both
\n" ); document.write( "side of the symbol. \"A ⊆ A\" is true but \"A ⊂ A\" is false. \r
\n" ); document.write( "\n" ); document.write( "⊆ allows (but does not require) that the set on the left of ⊆
\n" ); document.write( "contain ALL the members of the set on the right of ⊆. The
\n" ); document.write( "symbol ⊂ does not allow that the set on the left contain ALL
\n" ); document.write( "the elements of the set on the right of it. IOW, \r
\n" ); document.write( "\n" ); document.write( "{t,o,p} ⊆ {p,o,t} is true\r
\n" ); document.write( "\n" ); document.write( "but\r
\n" ); document.write( "\n" ); document.write( "{t,o,p} ⊂ {p,o,t} is false\r
\n" ); document.write( "\n" ); document.write( "To put it another way:\r
\n" ); document.write( "\n" ); document.write( "The only \"improper subset\" is the set itself, because it's
\n" ); document.write( "not properly \"sub\" which means \"less than\".\r
\n" ); document.write( "\n" ); document.write( "---------------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "B ⊂ A\r
\n" ); document.write( "\n" ); document.write( "A = {r, i, s, k, e, d}, B = {r, i, s, e}, C = {s, i, r}\r
\n" ); document.write( "\n" ); document.write( "That is true because every member of of B = {r, i, s, e}
\n" ); document.write( "is also a member of A = {r, i, s, k, e, d} yet B is not
\n" ); document.write( "equal to A. So B is a PROPER subset of A
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\n" ); document.write( "----------------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "A ⊂ C\r
\n" ); document.write( "\n" ); document.write( "A = {r, i, s, k, e, d}, B = {r, i, s, e}, C = {s, i, r}\r
\n" ); document.write( "\n" ); document.write( "That is false because not every member of of
\n" ); document.write( "A = {r, i, s, k, e, d} is a member of C = {s, i, r}, since
\n" ); document.write( "C has no k, e, or d. So B is a subset of A.\r
\n" ); document.write( "\n" ); document.write( "-----------------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "B ⊆ A\r
\n" ); document.write( "\n" ); document.write( "A = {r, i, s, k, e, d}, B = {r, i, s, e}, C = {s, i, r}\r
\n" ); document.write( "\n" ); document.write( "That is true because every member of of B = {r, i, s, e}
\n" ); document.write( "is also a member of A = {r, i, s, k, e, d}. So B is a PROPER
\n" ); document.write( "subset of A. B doesn't contain ALL of A\r
\n" ); document.write( "\n" ); document.write( "-----------------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "C ⊆ A\r
\n" ); document.write( "\n" ); document.write( "A = {r, i, s, k, e, d}, B = {r, i, s, e}, C = {s, i, r}\r
\n" ); document.write( "\n" ); document.write( "That is true because every member of of C = {s, i, r}
\n" ); document.write( "is also a member of A = {r, i, s, k, e, d}. So C is a PROPER
\n" ); document.write( "subset of A.\r
\n" ); document.write( "\n" ); document.write( "-----------------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "C ⊆ B \r
\n" ); document.write( "\n" ); document.write( "A = {r, i, s, k, e, d}, B = {r, i, s, e}, C = {s, i, r}\r
\n" ); document.write( "\n" ); document.write( "That is true because every member of of C = {s, i, r}
\n" ); document.write( "is also a member of B = {r, i, s, e}. So C is a PROPER subset
\n" ); document.write( "of B.\r
\n" ); document.write( "\n" ); document.write( "----------------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "So only A ⊂ C of the above statements is false.\r
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\n" ); document.write( "\n" ); document.write( "Edwin
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