document.write( "Question 476213: a. Solve for x
\n" ); document.write( "b. Rewrite the answer so that each individual logarithm from part a is written as a sum or difference of logarithms of prime numbers\r
\n" ); document.write( "\n" ); document.write( "\"+5%2F%283-e%5E%28-x%29%29+=+7+\"
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Algebra.Com's Answer #326565 by Tatiana_Stebko(1539)\"\" \"About 
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a. \"+5%2F%283-e%5E%28-x%29%29+=+7+\" multiply both sides by \"%283-e%5E%28-x%29%29\"
\n" ); document.write( "\"+5=+7%2A%283-e%5E%28-x%29%29++\"divide by 7
\n" ); document.write( "\"3-e%5E%28-x%29+=5%2F7\" subtract 3
\n" ); document.write( "\"-e%5E%28-x%29+=5%2F7-3\" divide by -1
\n" ); document.write( "\"e%5E%28-x%29+=-5%2F7%2B3\"
\n" ); document.write( "\"e%5E%28-x%29+=16%2F7\" logarithm
\n" ); document.write( "\"-x=ln%2816%2F7%29\" divide by -1
\n" ); document.write( "\"x=-ln%2816%2F7%29\"
\n" ); document.write( "If use the scintific calculator \"x=-0.8267\"
\n" ); document.write( ".
\n" ); document.write( "b. Rewrite the answer so that each individual logarithm from part a is written as a sum or difference of logarithms of prime numbers
\n" ); document.write( "\"x=-ln%2816%2F7%29\"
\n" ); document.write( "Use formula \"ln%28a%2Fb%29=lna-lnb\"
\n" ); document.write( "\"x=-%28ln16-ln7%29\"
\n" ); document.write( "\"x=ln7-ln16\"
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