document.write( "Question 476237: The perimeter of a rectangle is 252 inches. The length exceeds the width by 56 inches. Find the length and the width. \n" ); document.write( "
Algebra.Com's Answer #326556 by ccs2011(207)\"\" \"About 
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2L + 2W = 252
\n" ); document.write( "L = W + 56
\n" ); document.write( "Use substitution
\n" ); document.write( "2(W+56) + 2W = 252
\n" ); document.write( "Distribute
\n" ); document.write( "2W + 112 + 2W = 252
\n" ); document.write( "Combine like terms
\n" ); document.write( "4W = 140
\n" ); document.write( "Divide by 4 on both sides
\n" ); document.write( "W = 35
\n" ); document.write( "L = 35 + 56 = 91
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