document.write( "Question 476237: The perimeter of a rectangle is 252 inches. The length exceeds the width by 56 inches. Find the length and the width. \n" ); document.write( "
Algebra.Com's Answer #326556 by ccs2011(207)![]() ![]() You can put this solution on YOUR website! 2L + 2W = 252 \n" ); document.write( "L = W + 56 \n" ); document.write( "Use substitution \n" ); document.write( "2(W+56) + 2W = 252 \n" ); document.write( "Distribute \n" ); document.write( "2W + 112 + 2W = 252 \n" ); document.write( "Combine like terms \n" ); document.write( "4W = 140 \n" ); document.write( "Divide by 4 on both sides \n" ); document.write( "W = 35 \n" ); document.write( "L = 35 + 56 = 91 \n" ); document.write( " |