document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=476118>Question 476118</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I was looking on a website that teaches linear algebra and it had this problem:\r<BR>\n" );
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document.write( "(3x - 15)/(2x + 1) = 0\r<BR>\n" );
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document.write( "And it says the answer is: x = 5\r<BR>\n" );
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document.write( "But I don't understand how to get that answer so I was hoping someone can give me step by step directions for it. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #326519 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=326519\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This doesn't look like linear algebra...linear algebra deals with matrices, determinants, vector spaces, and so on.\r<BR>\n" );
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document.write( "Anyway, we set the numerator to zero, i.e. set 3x - 15 = 0. Solving for x we get x = 5. We want to make sure the denominator is nonzero so we can plug in x = 5 into the denominator. The denominator is nonzero, so x = 5 works. </SPAN>\n" );
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